1=-2v^2-2v

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Solution for 1=-2v^2-2v equation: 



1=-2v^2-2v

We move all terms to the left:

1-(-2v^2-2v)=0

We get rid of parentheses

2v^2+2v+1=0

a = 2; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·2·1
Δ = -4
Delta is less than zero, so there is no solution for the equation

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